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memcpy.c

/* Memcpy.c - Copy a block of memory
   Copyright (C) 1995, 1996 Malc Arnold.

   This program is free software; you can redistribute it and/or modify
   it under the terms of the GNU General Public License as published by
   the Free Software Foundation; either version 2, or (at your option)
   any later version.

   This program is distributed in the hope that it will be useful,
   but WITHOUT ANY WARRANTY; without even the implied warranty of
   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
   GNU General Public License for more details.

   You should have received a copy of the GNU General Public License
   along with this program; if not, write to the Free Software
   Foundation, Inc., 675 Mass Ave, Cambridge, MA 02139, USA.  */


#include <stdio.h>

/****************************************************************************/
/* RCS info. */

#ifndef lint
static char *RcsId = "$Id: memcpy.c,v 2.0 1997/09/06 11:56:40 malc Rel $";
#endif /* ! lint */

/****************************************************************************/
/*LINTLIBRARY*/
/****************************************************************************/
char *memcpy(buf, src, len)
char *buf, *src;
int len;
{
      /* Copy len bytes from src into buf */

      char *rbuf = buf;
      int c;

      /* This is pretty simple really */

      for (c = 0; c < len; c++) {
            *buf++ = *src++;
      }
      return(rbuf);
}
/****************************************************************************/

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